Question 628016
I'm assuming that both games were played on the same day (Saturday). One was played during the day and the other was played at night.



Let D = number who attended the day game and N = number who attended the night game


Since "The attendance at the Saturday night baseball game was three times the attendance at Saturday's (daytime) game" this means that 


N = 3D


Also, "In all, 56,000 fans attend the games", which tells us that


N + D = 56000


-------------------------------------------------------------------------


N + D = 56000 ... Start with the second equation


3D + D = 56000 ... Plug in N = 3D 


In other words, we replace N with 3D


Now solve for D


3D + D = 56000


4D = 56000 ... Combine like terms.


D = 56000/4 ... Divide both sides by 4.


D = <font color="red">14000</font> ... Divide


So <font color="red">14000</font> people attended the game during the day.



Since we know that D = 14000, we can use this to find N


N = 3D


N = 3(14000)


N = <font color="red">42000</font>


So <font color="red">42000</font> people went to the night game.



<font color="red">--------------------------------------------------------------------------------------------------------------</font>
If you need more help, email me at <a href="mailto:jim_thompson5910@hotmail.com?Subject=I%20Need%20Algebra%20Help">jim_thompson5910@hotmail.com</a>


Also, please consider visiting my website: <a href="http://www.freewebs.com/jimthompson5910/home.html">http://www.freewebs.com/jimthompson5910/home.html</a> and making a donation. Thank you


Jim
<font color="red">--------------------------------------------------------------------------------------------------------------</font>