<PRE><B>Question 625744</B>
Let the three (3) consecutive odd integers be:

n + 1

n + 3

n + 5

Add the above:

3n + 9 = 33

Subtract 9 from each side of the equation

3n + 9 - 9 = 33 - 9

Combine like terms:

9 - 9 = 0

33 - 9 = 24

Therefore:

3n = 24

Divide each side by 3

3n/3 = 24/3

n = 8

Therefore:

n + 1 = 8 + 1 = 9

n + 3 = 8 + 3 = 11

n + 5 = 8 + 5 = 13

9 + 11 + 13 = 33

Therefore:

The three consecutive odd integers (numbers) are:


9, 11 and 13



obuong3@aol.com</PRE>