Question 627880
<pre>
2(cis{{{pi/6}}}) = 2(cos{{{pi/6}}} + i·sin{{{pi/6}}}) = 2({{{sqrt(3)/2}}} + i·{{{1/2}}}) = 2·{{{sqrt(3)/2}}} + 2i·{{{1/2}}} =  {{{sqrt(3)}}} + i

 

Edwin</pre>