Question 627857
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Hi,
Will let you finish Up and solve for x
1) Three-fourths of a number{{{highlight(x)}}} is 7/8. {{{(3/4)x = 7/8}}}
 2)The <u>sum</u> of four times a number{{{highlight(x)}}} and 8 is equal to the <u>difference</u> of twice the number and 2.    {{{ 4x+ 8 = 2x-2 }}}
 3)Solve the inequality. Express the solution set in set-builder notation 36x+12 &#8804 6(5x+5)  &#8658;    30x &#8804; 18