Question 627770
{{{(2x-3)(x+3)}}} Start with the given expression.



Now let's FOIL the expression.



Remember, when you FOIL an expression, you follow this procedure:



{{{(highlight(2x)-3)(highlight(x)+3)}}} Multiply the <font color="red">F</font>irst terms:{{{(2*x)*(x)=2*x^2}}}.



{{{(highlight(2x)-3)(x+highlight(3))}}} Multiply the <font color="red">O</font>uter terms:{{{(2*x)*(3)=6*x}}}.



{{{(2x+highlight(-3))(highlight(x)+3)}}} Multiply the <font color="red">I</font>nner terms:{{{(-3)*(x)=-3*x}}}.



{{{(2x+highlight(-3))(x+highlight(3))}}} Multiply the <font color="red">L</font>ast terms:{{{(-3)*(3)=-9}}}.



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So we have the terms: {{{2*x^2}}}, {{{6*x}}}, {{{-3*x}}}, {{{-9}}} 



{{{2*x^2+6*x-3*x-9}}} Now add every term listed above to make a single expression.



{{{2x^2+3x-9}}} Now combine like terms.



So {{{(2x-3)(x+3)}}} FOILs to {{{2x^2+3x-9}}}.



In other words, {{{(2x-3)(x+3)=2x^2+3x-9}}}.


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