Question 627719
{{{20-x/3=x/2}}} Start with the given equation.



{{{6(20-x/cross(3))=6(x/cross(2))}}} Multiply both sides by the LCD {{{6}}} to clear any fractions.



{{{120-2x=3x}}} Distribute and multiply.



{{{-2x=3x-120}}} Subtract {{{120}}} from both sides.



{{{-2x-3x=-120}}} Subtract {{{3x}}} from both sides.



{{{-5x=-120}}} Combine like terms on the left side.



{{{x=(-120)/(-5)}}} Divide both sides by {{{-5}}} to isolate {{{x}}}.



{{{x=24}}} Reduce.



----------------------------------------------------------------------


Answer:


So the solution is {{{x=24}}} 


<font color="red">--------------------------------------------------------------------------------------------------------------</font>
If you need more help, email me at <a href="mailto:jim_thompson5910@hotmail.com?Subject=I%20Need%20Algebra%20Help">jim_thompson5910@hotmail.com</a>


Also, please consider visiting my website: <a href="http://www.freewebs.com/jimthompson5910/home.html">http://www.freewebs.com/jimthompson5910/home.html</a> and making a donation. Thank you


Jim
<font color="red">--------------------------------------------------------------------------------------------------------------</font>