Question 627696
<font face="Times New Roman" size="+2">


You need the Law of Cosines to find the measure of side *[tex \LARGE c].  Once you have done that, you need the Law of Sines to find the other two angles.


Law of Cosines:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ c^2\ =\ a^2\ +\ b^2\ -\ ab\,\cdot\,\cos(C)]


Plug in the numbers and do the arithmetic.  Don't forget to take the positive square root to find *[tex \LARGE c] from *[tex \LARGE c^2] at the end.


Law of Sines:


Once you know the value of *[tex \LARGE c], use:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{\sin(A)}{a}\ =\ \frac{\sin(B)}{b}\ =\ \frac{\sin(C)}{c}]


Solve


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{\sin(A)}{a}\ =\ \frac{\sin(C)}{c}]


for


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sin(A)]


Which you can do because you know (or can look up) *[tex \LARGE a], *[tex \LARGE c], and *[tex \LARGE \sin(C)]


Then look up


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sin^{-1}\left(\sin(A)\right)]


which gives you the measure of angle *[tex \LARGE A].


Repeat the law of sines process for angle *[tex \LARGE B].


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<div style="text-align:center"><a href="http://outcampaign.org/" target="_blank"><img src="http://cdn.cloudfiles.mosso.com/c116811/scarlet_A.png" border="0" alt="The Out Campaign: Scarlet Letter of Atheism" width="143" height="122" /></a></div>
</font>