Question 627669


Start with the given system of equations:

{{{system(3x-5y=17,9x-15y=-4)}}}



{{{-3(3x-5y)=-3(17)}}} Multiply the both sides of the first equation by -3.



{{{-9x+15y=-51}}} Distribute and multiply.



So we have the new system of equations:

{{{system(-9x+15y=-51,9x-15y=-4)}}}



Now add the equations together. You can do this by simply adding the two left sides and the two right sides separately like this:



{{{(-9x+15y)+(9x-15y)=(-51)+(-4)}}}



{{{(-9x+9x)+(15y+-15y)=-51+-4}}} Group like terms.



{{{0x+0y=-55}}} Combine like terms.



{{{0=-55}}}Simplify.



Since {{{0=-55}}} is <font size="4"><b>NEVER</b></font> true, this means that there are no solutions. 


So the system is inconsistent.


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