Question 627666
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You have the product of two conjugates, hence the difference of two squares.  Follow the pattern:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (a\ +\ b)(a\ -\ b)\ =\ a^2\ -\ b^2]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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