Question 627578


if three times a number {{{x}}} minus {{{7}}} is less then {{{17}}} and greater then {{{5}}}, we have

{{{5<x-7<17}}}...add {{{7}}} to all sides

{{{5+7<x-7+7<17+7}}}

{{{12<x<24}}}...so, {{{x}}} could be any number between {{{12}}} and {{{24}}}

solutions:

{{{x=13}}}, {{{x=14}}}, {{{x=15}}},{{{x=16}}},{{{x=17}}},{{{x=18}}},{{{x=19}}},{{{x=20}}},{{{x=21}}},{{{x=22}}}, or {{{x=23}}}