Question 627424


{{{(2x+3)^2=10}}} Start with the given equation.



{{{2x+3=""+-sqrt(10)}}} Take the square root of both sides.



{{{2x+3=sqrt(10)}}} or {{{2x+3=-sqrt(10)}}} Break up the "plus/minus" to form two equations.



{{{2x=-3+sqrt(10)}}} or {{{2x=-3-sqrt(10)}}} Subtract {{{3}}} from both sides.



{{{x=(-3+sqrt(10))/2}}} or {{{x=(-3-sqrt(10))/2}}} Divide both sides by 2.



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Answer:



So the solutions are {{{x=(-3+sqrt(10))/2}}} or {{{x=(-3-sqrt(10))/2}}}.


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