Question 627409
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(5,0\right)]. So this means that {{{x[1]=5}}} and {{{y[1]=0}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(6,8\right)].  So this means that {{{x[2]=6}}} and {{{y[2]=8}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(8-0)/(6-5)}}} Plug in {{{y[2]=8}}}, {{{y[1]=0}}}, {{{x[2]=6}}}, and {{{x[1]=5}}}



{{{m=(8)/(6-5)}}} Subtract {{{0}}} from {{{8}}} to get {{{8}}}



{{{m=(8)/(1)}}} Subtract {{{5}}} from {{{6}}} to get {{{1}}}



{{{m=8}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(5,0\right)] and *[Tex \LARGE \left(6,8\right)] is {{{m=8}}}


<font color="red">--------------------------------------------------------------------------------------------------------------</font>
If you need more help, email me at <a href="mailto:jim_thompson5910@hotmail.com?Subject=I%20Need%20Algebra%20Help">jim_thompson5910@hotmail.com</a>


Also, please consider visiting my website: <a href="http://www.freewebs.com/jimthompson5910/home.html">http://www.freewebs.com/jimthompson5910/home.html</a> and making a donation. Thank you


Jim
<font color="red">--------------------------------------------------------------------------------------------------------------</font>