Question 627304
{{{(7-a)(4-3a)}}}


{{{7(4-3a)-a(4-3a)}}}


{{{28-21a-4a+3a^2}}}


{{{28-25a+3a^2}}}


{{{3a^2-25a+28}}}


So {{{(7-a)(4-3a)}}} multiplies out to {{{3a^2-25a+28}}}


In other words, {{{(7-a)(4-3a)=3a^2-25a+28}}} for all values of 'a'.


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