Question 627187
log (2y) + log (4y-1) = 2
log [2y(4y-1)] = 2
log (8y^2 - 2y) = 2
10^2=8y^2 - 2y
100=8y^2 - 2y
0=2(4y^2-y-50)
y= [-(-1) +/- sqrt (-1)^2-4*4*(-50)]/ 2*4
y=[1 +/- (sqrt 1 + 800)]/8