<PRE><B>Question 627119</B>
(4x-1)(x^2+5x-2)


4x(x^2+5x-2) - 1(x^2+5x-2)


4x(x^2)+4x(5x)4x(-2) - 1(x^2)-1(5x)-1(-2)


4x^3+20x^2-8x - 1x^2-5x+2


4x^3+19x^2-13x+2


So (4x-1)(x^2+5x-2) expands out to 4x^3+19x^2-13x+2</PRE>