Question 627021
{{{p^2 - 7p = 30}}}


{{{p^2 - 7p - 30 = 0}}}


Now use the quadratic formula to solve for p:


{{{p = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{p = (-(-7)+-sqrt((-7)^2-4(1)(-30)))/(2(1))}}}


{{{p = (7+-sqrt(49-(-120)))/(2)}}}


{{{p = (7+-sqrt(169))/2}}}


{{{p = (7+sqrt(169))/2}}} or {{{p = (7-sqrt(169))/2}}}


{{{p = (7+13)/2}}} or {{{p = (7-13)/2}}}


{{{p = 20/2}}} or {{{p = -6/2}}}


{{{p = 10}}} or {{{p = -3}}}


So the solutions are {{{p = 10}}} or {{{p = -3}}}