Question 627156
{{{log(x,(1/8)) = -3}}} Start with the given equation.



{{{x^(-3) = 1/8}}} Convert to exponential form



{{{x^(-3) = 2^(-3)}}} Rewrite {{{1/8}}} as {{{2^(-3)}}}



Since the exponents are equal, the bases must be equal



So {{{x=2}}} is the solution.


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