<PRE><B>Question 627114</B>
How do I find the area of a triangle that has the side measurements of 6.2, 6.9, and 8.4? There are no angles given.
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You can use Heron&#39;s Law
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s = Perimeter/2 = (6.2+6.9+8.4)2
s = 10.75
a = 6.2
b = 6.9
c = 8.4
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{{{Area = sqrt(s(s-a)*(s-b)*(s-c))}}}
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Or, you can use the Cosine Law to find an angle, then find the area.
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