Question 627054
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Let *[tex \LARGE x] represent the first of three consecutive integers.  Then *[tex \LARGE x\ +\ 1] is the next consecutive integer and *[tex \LARGE x\ +\ 2] is the one after that.


The first integer:  *[tex \LARGE x]


The first integer increased by twice the second:  *[tex \LARGE x\ +\ 2(x\ +\ 1)]


Exceeds the third by 10:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ 2(x\ +\ 1)\ =\ (x\ +\ 2)\ +\ 10]


Solve for *[tex \LARGE x], then calculate *[tex \LARGE x\ +\ 1] and *[tex \LARGE x\ +\ 2]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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