Question 627091
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(5,-2\right)]. So this means that {{{x[1]=5}}} and {{{y[1]=-2}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(-3,-1\right)].  So this means that {{{x[2]=-3}}} and {{{y[2]=-1}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-1--2)/(-3-5)}}} Plug in {{{y[2]=-1}}}, {{{y[1]=-2}}}, {{{x[2]=-3}}}, and {{{x[1]=5}}}



{{{m=(1)/(-3-5)}}} Subtract {{{-2}}} from {{{-1}}} to get {{{1}}}



{{{m=(1)/(-8)}}} Subtract {{{5}}} from {{{-3}}} to get {{{-8}}}



{{{m=-1/8}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(5,-2\right)] and *[Tex \LARGE \left(-3,-1\right)] is {{{m=-1/8}}}


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