Question 627072
(a-b)^2 = (a-b)(a-b)


(a-b)^2 = (-1(-a+b))(-1(-a+b))


(a-b)^2 = (-1)*(-1)*(-a+b)*(-a+b)


(a-b)^2 = (-1)*(-1)*(b-a)*(b-a)


(a-b)^2 = 1*(b-a)*(b-a)


(a-b)^2 = (b-a)(b-a)


(a-b)^2 = (b-a)^2


That last equation is true for all values of 'a' and 'b'


In this case, a = x and b = 4, so


(a-b)^2 = (b-a)^2


becomes


(x-4)^2 = (4-x)^2


which is true for all values of x



So they are both correct.

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