Question 627059
{{{w(w-2)=8}}}


{{{w^2-2w=8}}}


{{{w^2-2w-8=0}}}


Now use the quadratic formula to solve for x


{{{w = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{w = (-(-2)+-sqrt((-2)^2-4(1)(-8)))/(2(1))}}}


{{{w = (2+-sqrt(4-(-32)))/(2)}}}


{{{w = (2+-sqrt(36))/2}}}


{{{w = (2+sqrt(36))/2}}} or {{{w = (2-sqrt(36))/2}}}


{{{w = (2+6)/2}}} or {{{w = (2-6)/2}}}


{{{w = 8/2}}} or {{{w = -4/2}}}


{{{w = 4}}} or {{{w = -2}}}


So the solutions are {{{w = 4}}} or {{{w = -2}}}


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