<PRE><B>Question 626936</B>
a car runs 10 km an hour faster than a jeepney. Find the rate of each if the car can travel 200 km one hour less than that of the jeepney.
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Car DATA:
rate = x kmh ; distance = 200 km ; time = d/r = 200/x hrs.
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Jeep DATA:
rate = x-10 kmh ; distance = 200 km ; time = d/r = 200/(x-10) hrs
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Equation:
jeep time - car time = 1 hour
200/(x-10) - 200/x = 1
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Multiply thru by x(x-10) to get:
200x - 200(x-10) = x(x-10)
2000 = x^2-10x
x^2-10x-2000 = 0
(x-50)(x+40) = 0
x = 50 kmh (rate of the car
x-10 = 40 kmh (rate of the jeep)
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Cheers,
Stan H.
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