Question 57766
Given: 2w(4w+1)=1
We know that 2*w*(4*w+1)=1 (which simply shows the computations).

Using the distributive property: 2w(4w+1)=8w^2+2w

So 2w(4w+1)=1 becomes 8w^2+2w=1 or
8*w^2+2*2 (showing the computations).

Subtracting 1 from both sides of the equation: 8w^2+2w-1=0, which is standard form.

We cannot factor 8w^2+2w-1 into simpler terms, so we have to use the quadratic equation: {{{x = (-b +- sqrt(b^2-4*a*c))/(2*a)}}}.


Consequently, {{{ x = (-2 +- sqrt(2^2 - 8*4*(-1)))/(2*8)}}}.


This simplifies to {{{ x = (-2 +- 6)/16 }}}.


So x = .25 or -.5.