Question 626810
Find an equation of the line with a x-intercept of 26 that is perpendicular
 to the line given by 4x-y=3. Leave your answer in the form ax+by=c
:
4x - y = 3
put into the slope intercept form
-y = -4x + 3
Multiply both sides by -1
y = 4x - 3
slope of the line: m1 = 4
:
Perpendicular line slope relationship; m1*m2 = -1
4*m1 =-1
m1 = {{{-1/4}}}
m1 = -.25, slope of the perpendicular line
x intercept = 26, y = 0
:
Use the point/slope form: y - y1 = m(x - x1) 
y - 0 = -.25(x - 26)
y = -.25x + 6.5
"Leave your answer in the form ax+by=c"
.25x + y = 6.5
get rid of the decimals, multiply by 4
x + 4y = 26