Question 626718
Add. Simplify, if possible.
{{{(49b)/(7b-49)}}} + {{{(3b)/(49b-343)}}}.
:
Factor both denominators
{{{(49b)/(7(b-7))}}} + {{{(3b)/(49(b-7))}}}.
:
Cancel 7; common denominator 49(b-7)
{{{(7b)/((b-7))}}} + {{{(3b)/(49(b-7))}}} = {{{(49(7b)+3b)/(49(b-7))}}} = {{{(343b+3b)/(49(b-7))}}} = {{{(346b)/(49(b-7))}}}