Question 626670
There are 53 choices for the first number, 52 for the second, 51 for the third, 50 for the fourth and 49 for the fifth.<P>
That means there are a total of 53*52*51*50*49=344,362,200 possible combinations.<P>
The probability of one selection winning is 1/344,362,200=2.9 x 10^-9 approx. (2.9x10^-7 %)
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