Question 626662
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Hi,
the smallest of three consecutives integers{{{highlight(x)}}},{{{highlight(x+1)}}}, {{{highlight(x+2)}}}
is added to twice the largest, the result so obtained is 15 less than four timess the middle integer.
Question states***
  x + 2(x+2) = 4(x+1) - 15
    3x + 4 = 4x + 4 - 15
         15 = x
The three consecutives integers are 15, 16, 17
and
 {{{15 + 2*17 = 49 =  4*16 - 15}}}