Question 626359
Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. 
F(x)=3x^2-12x+3
Complete the square
F(x)=3(x^2-4x+4)+3-12
F(x)=3(x-2)^2-9
This is an equation of a parabola that opens upwards (curve has a minimum)
Its standard form of equation: y=(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex
..
What is the vertex? (2,-9)
What is the equation of the line of symmetry? x=2
What is the minimum of f(x)? -9
The value, f(2)= -9 is a minimum 
See graph below:
{{{ graph( 300, 300, -10, 10, -10, 10,3x^2-12x+3) }}}