Question 626471
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Your picture is a little whack as compared to your description.  If the measure of angle A is indeed 96 degrees, then A has to be the vertex angle of your isosceles triangle.  That's because if one of the base angles measured 96 degrees, then the other base angle must also measure 96 degrees, and you cannot have two angles greater than or equal to 90 degrees in any triangle -- and that is because the sum of the measures of the angles in any triangle is 180 degrees.  So you see two 96 degree angles would mean that you have the sum of the interior angles at greater than 192 degrees -- impossible.


So, given that the vertex (or apex if you would rather) measures 96 degrees, subtract 96 from 180 and divide what you have left by 2 giving you the measure of your two base angles.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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