Question 626003
<pre>
{{{system(3x+2y=5,  1x-2y=4)}}}

Add corresponding terms, using the principle 

"Equals added to equals give equals"

{{{system(3x+2y=5,  1x-2y=4,"_________")}}}
 {{{system(4x+0y=9)}}} <- Notice that the y terms were eliminated.
 
    4x = 9
     x = {{{9/4}}}

Now let's eliminate the x-terms.  To do that we have to make the
x-terms cancel out like the y-terms did in the first case.

{{{system(3x+2y=5,  1x-2y=4)}}}

Let's multiply the second equation through by -3 so that the 1x
will become -3x and will cancel with the 3x in the first
equation:



{{{system(""+3x+2y=5,  -3x+6y=-12,"_________")}}}
 {{{system(""+0x+8y=-7)}}} <- Notice that the x terms were eliminated.
 
    8y = -7
     y = {{{(-7)/8}}}
     y = {{{-7/8}}}

Solution: If the lines were graphed they would intersect at

the point ({{{9/4}}},{{{-7/8}}})
     
Edwin</pre>