Question 625811
{{{(t^2 - 4t - 32)/(t - 8)}}}


{{{((t - 8)(t + 4))/(t - 8)}}}


{{{t + 4}}}


So {{{(t^2 - 4t - 32)/(t - 8)}}} simplifies to {{{t + 4}}} where {{{t<>8}}} to avoid dividing by zero.

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