Question 57664
Not sure how you got the 0 in the denominator there.  Here is one way to solve for Z, given this equation: {{{17+3(z-2)-11z=-7(z/2)+14}}}

{{{17+3z-3*2-11z=-(7/2)z+ 14}}}
{{{-8z+11 = -3.5z +14}}}
{{{-4.5z=3}}}
{{{z=-3/4.5}}}
{{{z=-2/3}}}