<PRE><B>Question 625699</B>
The first part of the trip takes 2 hours.  Since the total trip takes 9 hours and it takes 1 hour for gas and lunch, the last part of the trip takes 6 hours.
Let s = the initial speed
The distance covered in the 1st part of the trip = 2*s
The distance covered in the 2nd part of the trip = 6(s-20) [speed reduced by 20 mph]
Since the total distance = 400 mi, we can write
400 = 2s + 6(s-20)
Solve for s:
400 = 8s - 120
8s = 520
s = 65
So the initial speed is 65 mph</PRE>