Question 625669
7x^2-6(sq3)xy+13y^2-16 = 0
{{{14xdx - 6sqrt(3)*(ydx + xdy) + 26ydy = 0}}}
{{{(14x - 6sqrt(3)y)dx + (26y - 6sqrt(3)x)dy = 0}}}
dy/dx = -(14x - 6sqrt(3)y)/(26y - 6sqrt(3)x)
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f'(sqrt(3),1) = -(14sqrt(3) - 6sqrt(3))/(26 - 18)
= - sqrt(3) slope of tangent line
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y = mx + b
1 = -3 + b
b = 4
--> y = -sqrt(3)*x + 4
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