Question 625625
Find the vertex, line of symmetry, and the maximum or minimum value of f(x).

f(x)=  1/2 〖(x+3)〗^2+1
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Why do you go to the trouble to make it unreadable?
f(x)=  1/2(x+3)^2+1
It's in standard form:
Vertex @ (-3,1)
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LOS is x = -3
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The coeff of x^2 is positive --> minimum.
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Min is at the vertex, = 1