Question 625553
A car starting from rest moves down on an inclined road with a uniform acceleration . It travels for 100 m in 10 secs . The speed of car at the end of 10 sec is nearly
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Its average speed = 100/10 = 10 m/sec
It starts at zero --> end speed = 20 m/sec
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Or
s = at^2/2
a = 2s/t^2 = 200/100 = 2 m/sec/sec
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v = a*t = 2*10
v = 20 m/sec