Question 57653
YOU'VE BEEN GIVEN A POINT AND A SLOPE AND ASKED FOR AN EQUATION OF A LINE.  THAT IS YOUR CLUE THAT YOU SHOULD USE THE POINT SLOPE FORMULA.
{{{highlight(y-y1=m(x-x1))}}}, where m=slope, and (x1,y1) is the given point.
Graph the line described: Through (-2,-3);m = 5/4
x1=-2, y1=-3, m=5/4
{{{y-(-3)=(5/4)(x-(-2))}}}
{{{y+3=(5/4)(x+2)}}}  Avoid adding fractions if you want by multiplying both sides by the LCD,4.
{{{4(y+3)=4(5/4)(x+2)}}}
{{{4y+12=5(x+2)}}}
{{{4y+12=5x+10}}}
{{{4y+12-12=5x+10-12}}}
{{{4y=5x-2}}}
{{{-5x+4y=-5x+5x-2}}}
{{{-5x+4y=-2}}}  This is the equation in standard form, but some books don't lead with a negative x.  If this is the case, then multiply both sides of the equation by -1.
{{{5x-4y=2}}}  Is also in standard form.
I forgot to graph this earlier, sorry.
Plot (-2,-3) , then use the slope=rise/run=5/4.  Go up from that point and right 4 and plot a second point at (2,2).  Connect the dots and you should have this line:
{{{graph(300,200,-10,10,-10,10,(5/4)(x+2)-3)}}}
Happy Calculating!!!