<PRE><B>Question 625523</B>
start with:
sqrt(5x+5) = x+1
square both sides of this equation to get:
5x+5 = (x+1)^2
simplify to get:
5x+5 = x^2+2x+1
subtract 5x and subtract 5 from both sides of the equation to get:
0 = x^2-3x-4
this is the same as:
x^2-3x-4 = 0
factor this quadratic equation to get:
(x-4)*(x+1) = 0
solve for x to get:
x=4, x=-1
both of these solutions are good as you will see when you substitute for x in the original equation using each in turn.
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