Question 625526
Not sure where to put this - it IS a quadratic function where I need to find the vertex, line of symmetry, the maximum or minimum value of the quadratic function. 
f(x) = -2x^2 + 2x + 1
complete the square
f(x)= -2(x^2-x+1/4)+1+1/2
f(x)= -2(x-1/2)^2+3/2
This is an equation that opens downwards.(negative coefficient of leading term)
Its standard form of equation: y=-(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex
..
The x-coordinate of the vertex is: 1/2
(Type a simplified fraction) 
The y-coordinate of the vertex is: 3/2
(Type a simplified fraction) 
The equation of the line of symmetry is x=1/2
(Type an equation. Use integers or fractions for any numbers in the equation.) 
The maximum of f(x) is: 3/2
(Type a simplified fraction.) 
The value of f(1/2) = (3/2) is a 
b) maximum