Question 625504
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You are confused?  So am I.  The numbers 100 and 140 are never part of the quadratic formula solution to the given equation.


For starters, notice that *[tex \LARGE (-2)^2\ - 3(4)(1)\ =\ -8\ <\ 0]


so your roots are conjugate pair of complex numbers.


The roots of


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ ax^2\ +\ bx\ +\ c\ =\ 0]


are given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ \frac{-b\ \pm\ \sqrt{b^2\ -\ 4ac}}{2a}]


Just plug in the numbers and do the arithmetic.  Just remember, *[tex \LARGE i^2\ =\ -1]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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