Question 625488
Those 3 consecutive odd integers are:  n, n+2 and n+4

7(n+n+4) = 10(-n-2)-120

7(2n+4) = -10n-20-120

14n+28 = -10n -140

14n + 10n = -140 -28

24n = -168

n = -168/24

n = -7

Answer: -7, -5 and -3

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