Question 624977

Probability of getting 4 in single throw = 1/6 

so, probability of net getting 4 in single throw = 5/6


probability of getting exactly two fours in five throw = 5C2* (1/6)^2 * (5/6)^3
( Binomial probability )

= 10 * 5^3 / (6^5)



I hope it will help you to understand the concept, feel free to ask if any doubt....