Question 625289
Well, first you rewrite the equation in 1 2 0 5 -3 form.  Then you turn x+2 into -2 becuase x+2=0. You have to set x equal 0, when you do that you get -2.  So, you rewrite the problem like this: -2/1 2 0 5 -3.  You add zero to the problem because the equation was x^4+2x^3+5x-3,and the x^2 was missing. For every missing value, you put zero when dividing. So, one goes to the bottom, then you multiply 1 by -2, and put it underneath 2. You add -2 to 2.  You get 0, then again you multiply 0 by -2, you get 0.  You put that under 0, and then add them.  You get 0, you multiply that by -2 agin. You get 0, you put that underneath 5 and add.  You get 5, so you multiply 5 by -2 and get -10.  Finally, you put that underneath -3 and then add. So, the remainder is -13. The equation is: x^3+0x^2+0x+5, with the remainder of -13!  Or just x^3+5 with r=-13.