Question 625290
Solve the following systems of equations and find all possible solutions as (x,y).

{{{y=2x-1}}}
{{{y=x^2-3x-1}}}
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2x-1 = x^2-3x-1
x^2 - 5x  =  0
x(x - 5) = 0
x= 0 or x = 5
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Cheers,
Stan H.