Question 625236
<pre>
There are 6 possibilities

{33665, 36365, 36635, 63365, 63635, 66335}

We will assume you will not try the same number twice.

We use the principle that "AND corresponds to MULTIPLICATION":

The probability of

{{{(matrix(6,1,

getting,it,wrong,the,first,time))}}}{{{matrix(6,1,

"","",and,"","","")}}}{{{(matrix(6,1,

getting,it,wrong,the,second,time))}}}{{{matrix(6,1,

"","",and,"","","")}}}{{{(matrix(6,1,

getting,it,wrong,the,third,time))}}} = P{{{(matrix(6,1,

getting,it,wrong,the,first,time))}}}×P{{{(matrix(6,1,

getting,it,wrong,the,second,time))}}}×P{{{(matrix(6,1,

getting,it,wrong,the,third,time))}}} = {{{5/6}}}×{{{4/5}}}×{{{3/4}}} = {{{1/2}}}

Edwin</pre>