Question 625141
f(x)=x^3-2x^2-11x+52

     1  -2  -11   52

-4      -4   24  -52

     1  -6   13    0

x^2-6x+13 =0

x = [6 +- sqrt(-16)]/2

= [6+-4i]/2

3+-2i

Answer: remaining zeros are: 3+2i and 3-2i

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