Question 624980
This solution works, too.<br>
The main reason it appears faster than my solutions is that many intermediate steps are being omitted. If I had done this my first solution would look like:
{{{(sqrt((1-cos(2x))/2))^4+(sqrt((1+cos(2x))/2))^4=3/4 + (1/4)cos(4x)}}}
{{{2/4+(2cos^2(2x))/4 = 3/4 + (1/4)cos(4x)}}}
{{{3/4+(1/4)cos(4x) = 3/4 + (1/4)cos(4x)}}}
And we're finished!<br>
And the second solution would be:
{{{(sin^2(x))^2+(cos^2(x))^2=3/4 + (1/4)cos(4x)}}}
{{{((-1/2)cos(2x) + 1/2)^2+((1/2)cos(2x) + 1/2)^2=3/4 + (1/4)cos(4x)}}}
{{{(1/2)cos^2(2x) + 1/2 = 3/4 + (1/4)cos(4x)}}}<br>
{{{(1/2)((1/2)cos(4x) + 1/2)  + 1/2 = 3/4 + (1/4)cos(4x)}}}
{{{(1/4)cos(4x) + 3/4 = 3/4 + (1/4)cos(4x)}}}