Question 625029
4x+3y=26..........(1)


y=3x
y-3x=0............(2)

Multiply (2) by 3 and subtract it from (1)
4x+3y=26
-3y+9x=0
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13x=26
Divide by 13 both sides of the above equation
13x/13=26/13
x=2

Put the value of x in (2)
y=3x
y=3(2)
y=6


(x,y)=(2,6)




Check
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Put the value of x and y in (1)
4x+3y=26..........(1)
4(2)+3(6)=26
8+18=26
26=26