Question 624924
If cotangent of theta is -7/4, what is the sine of theta and secant of theta?
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cot=adjacent side/opposite side=-7/4
hypotenuse=√(7^2+4^2)=√(49+16)=√65
For theta between 0 and π:
Reference angle is in quadrant II where cot<0
sin theta=opposite side/hypotenuse=4/&#8730;65
sec theta=hypotenuse/adjacent side=-&#8730;65/7